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Proof : Distribution Law of Union over Intersection A U (B ∩ C) = (A U B) ∩ (A U C)
Proof : Distribution Law of Intersection over Union A ∩ (B U C) = (A ∩ B) U (A ∩ C)
De Morgan’s Laws
Complement of a Union is the Intersection of Complements : (A U B)’ = A’ ∩ B’
Complement of a Intersection is the Union of Complements : (A ∩ B)’ = A’ U B’
Prove That A U (A ∩ B) = A
Prove That : A ∩ (A U B) = A & (A – B) ∩ (B – A) = Φ
n(A U B) = n(A) + n(B) – n (A ∩ B)
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